-8t^2=-7t

Solution for -8t^2=-7t equation:

-8t^2=-7t

We move all terms to the left:

-8t^2-(-7t)=0

We get rid of parentheses

-8t^2+7t=0

a = -8; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-8)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-8}=\frac{-14}{-16}
=7/8
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-8}=\frac{0}{-16}
=0
$